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Fix unit test / build - newly created model is not active by default, hence needs to be explicitly activated.

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git-svn-id: https://svn.alfresco.com/repos/alfresco-enterprise/alfresco/HEAD/root@6753 c4b6b30b-aa2e-2d43-bbcb-ca4b014f7261
This commit is contained in:
Jan Vonka
2007-09-11 08:17:07 +00:00
parent 9319f0bf92
commit 7e60152931
2 changed files with 4 additions and 1 deletions
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2
source/java/org/alfresco/repo/dictionary/DictionaryModelType.java
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@@ -353,7 +353,7 @@ public class DictionaryModelType implements ContentServicePolicies.OnContentUpda
{ {
public Object doWork() public Object doWork()
{ {
// Find out whether the model is active (by default it is) // Find out whether the model is active
boolean isActive = false; boolean isActive = false;
Boolean value = (Boolean)nodeService.getProperty(nodeRef, ContentModel.PROP_MODEL_ACTIVE); Boolean value = (Boolean)nodeService.getProperty(nodeRef, ContentModel.PROP_MODEL_ACTIVE);
if (value != null) if (value != null)

3
source/java/org/alfresco/repo/dictionary/DictionaryRepositoryBootstrapTest.java
View File

@@ -224,6 +224,9 @@ public class DictionaryRepositoryBootstrapTest extends BaseAlfrescoSpringTest
propertyName); propertyName);
contentWriter1.putContent(modelOne); contentWriter1.putContent(modelOne);
// activate the model
nodeService.setProperty(model, ContentModel.PROP_MODEL_ACTIVE, new Boolean(true));
return model; return model;
} }