arditdomi 6dc01c4b17
[ACA-3182] Add a way to define an extension route as child of a route (#1463)
* [ACA-3182] Add a way to define an extension route as child of a route

* [ACA-3182] Add unit tests

* [ACA-3182] Add license header
2020-05-12 09:39:33 +01:00

49 lines
1.5 KiB
TypeScript

/*!
* @license
* Alfresco Example Content Application
*
* Copyright (C) 2005 - 2020 Alfresco Software Limited
*
* This file is part of the Alfresco Example Content Application.
* If the software was purchased under a paid Alfresco license, the terms of
* the paid license agreement will prevail. Otherwise, the software is
* provided under the following open source license terms:
*
* The Alfresco Example Content Application is free software: you can redistribute it and/or modify
* it under the terms of the GNU Lesser General Public License as published by
* the Free Software Foundation, either version 3 of the License, or
* (at your option) any later version.
*
* The Alfresco Example Content Application is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
* GNU Lesser General Public License for more details.
*
* You should have received a copy of the GNU Lesser General Public License
* along with Alfresco. If not, see <http://www.gnu.org/licenses/>.
*/
import { Route } from '@angular/router';
export interface SettingsGroupRef {
id: string;
name: string;
parameters: Array<SettingsParameterRef>;
rules?: {
visible?: string;
[key: string]: string;
};
}
export interface SettingsParameterRef {
id?: string;
name: string;
key: string;
type: 'string' | 'boolean';
value?: any;
}
export interface ExtensionRoute extends Route {
parentRoute?: string;
}