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RM-2198: Can't classify a frozen record.

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* server integration tests added
 * UI integration tests added (based on adjusted acceptance critera on RM-2052)



git-svn-id: https://svn.alfresco.com/repos/alfresco-enterprise/modules/recordsmanagement/HEAD@104141 c4b6b30b-aa2e-2d43-bbcb-ca4b014f7261
This commit is contained in:
Roy Wetherall
2015-05-14 04:14:30 +00:00
parent 21893ae3f2
commit 8b18d50208
1 changed files with 32 additions and 0 deletions
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32
rm-server/test/java/org/alfresco/module/org_alfresco_module_rm/test/integration/classification/ClassifyTest.java
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@@ -23,6 +23,7 @@ import java.util.List;
import org.alfresco.module.org_alfresco_module_rm.classification.model.ClassifiedContentModel;
import org.alfresco.module.org_alfresco_module_rm.test.util.BaseRMTestCase;
import org.alfresco.repo.security.permissions.AccessDeniedException;
import org.alfresco.service.cmr.repository.NodeRef;
/**
@@ -38,6 +39,37 @@ public class ClassifyTest extends BaseRMTestCase
private static final String CLASSIFICATION_REASON = "Test Reason 1";
private static final String CLASSIFICATION_AUTHORITY = "classification authority";
private static final String RECORD_NAME = "recordname.txt";
/**
* Given that a record is frozen
* And unclassified
* When I set the initial classification
* Then a AccessDeniedException is raised
*/
public void testClassifyFrozenRecord() throws Exception
{
doBehaviourDrivenTest(new BehaviourDrivenTest(AccessDeniedException.class)
{
private NodeRef record;
public void given() throws Exception
{
record = utils.createRecord(rmFolder, RECORD_NAME);
NodeRef hold = holdService.createHold(filePlan, "my hold", "for test", "for test");
holdService.addToHold(hold, record);
}
public void when() throws Exception
{
classificationService.classifyContent(
CLASSIFICATION_LEVEL,
CLASSIFICATION_AUTHORITY,
Collections.singleton(CLASSIFICATION_REASON),
record);
}
});
}
/**
* Given that a record is complete